public int compareTo(Object o) {
		Card other = (Card)o;
		
		if( !suit.equals(other.suit) ){
			// if the suits aren't the same, just use the
			// Strings compareTo method to rank alphabetically
			return suit.compareTo(other.suit);
		}else{
			// Same suit, so rank by number
			if( number < other.number ){
				return -1;
			}else if( number > other.number ){
				return 1;
			}else{
				return 0;
			}
		}
	}

------ Extra Challenge -------
	public int compareTo(Object o) {
		Card other = (Card)o;
		
		if( !suit.equals(other.suit) ){
			// if the suits aren't the same, just use the
			// Strings compareTo method to rank alphabetically
			return suit.compareTo(other.suit);
		}else{
			// Same suit, so rank by number
			if( number == 1 ){
				if( other.number == 1 ){
					return 0;
				}else{
					// ace is bigger than everything
					return 1;
				}
			}else if( other.number == 1 ){
				// number cannot be 1
				return -1;
			}else{
				// neither are aces, so just the normal comparison
				if( number < other.number ){
					return -1;
				}else if( number > other.number ){
					return 1;
				}else{
					return 0;
				}
			}
		}
	}



	// NOTE: another option would be to re-encode the numbers for this class so that ace was the highest number